Difference between revisions of "JOIN Quiz 2"

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- SELECT name, COUNT(movieid) FROM casting JOIN actor WHERE (actorid ON actor.id) AND name LIKE 'John %' GROUP BY name ORDER BY 2 DESC
 
- SELECT name, COUNT(movieid) FROM casting JOIN actor WHERE (actorid ON actor.id) AND name LIKE 'John %' GROUP BY name ORDER BY 2 DESC
 
- SELECT name, COUNT(movieid) FROM casting JOIN actor WHERE name LIKE 'John %' GROUP BY name ORDER BY COUNT(movieid) DESC
 
- SELECT name, COUNT(movieid) FROM casting JOIN actor WHERE name LIKE 'John %' GROUP BY name ORDER BY COUNT(movieid) DESC
 +
 +
{Select the result that would be obtained from the following code: SELECT title FROM movie, casting, actor WHERE name='Paul Hogan' AND movieid=movie.id AND actorid=actor.id AND ord = 1
 +
|type="()"}
 +
- Table-A
 +
- Table-B
 +
- Table-C
 +
- Table-D
 +
+ Table-E
  
 
{Select the statement that lists all the actors that starred in movies directed by Ridley Scott
 
{Select the statement that lists all the actors that starred in movies directed by Ridley Scott

Revision as of 14:01, 7 August 2012

JOIN Quiz - part 2

1. Select the statement which lists the unfortunate directors of the movies which have caused financial loses (gross < budget)

SELECT JOIN(name FROM actor, movie ON actor.id:director WHERE gross < budget) GROUP BY name
SELECT name FROM actor INNER JOIN movie BY actor.id = director HAVING gross < budget
SELECT name FROM actor INNER JOIN movie ON actor.id = director WHERE gross < budget
SELECT name FROM actor INNER JOIN movie ON actor.id:director WHERE gross < budget
SELECT name FROM director INNER JOIN movie ON movie.id = director.id WHERE gross < budget

2. Select the correct example of JOINing three tables

SELECT * FROM actor JOIN casting BY actor.id = actorid JOIN movie BY movie.id = movieid
SELECT * FROM actor JOIN casting ON actor.id = actorid AND JOIN movie ON movie.id = movieid
SELECT * FROM actor JOIN casting JOIN movie ON actor.id = actorid AND movie.id = movieid
SELECT * FROM actor JOIN casting ON actor.id = actorid AND movie ON movie.id = movieid
SELECT * FROM actor JOIN casting ON actor.id = actorid JOIN movie ON movie.id = movieid

3. Select the statement that shows the list of actors called 'John' by order of number of movies in which they acted

SELECT name, COUNT(movieid) FROM actor JOIN casting ON actorid=actor.id WHERE name IN 'John %' GROUP BY name ORDER BY 2
SELECT name, COUNT(movieid) FROM actor JOIN casting ON actorid=actor.id WHERE name LIKE 'J%' GROUP BY name ORDER BY 2 DESC
SELECT name, COUNT(movieid) FROM casting JOIN actor ON actorid=actor.id WHERE name LIKE 'John %' GROUP BY name ORDER BY 2 DESC
SELECT name, COUNT(movieid) FROM casting JOIN actor WHERE (actorid ON actor.id) AND name LIKE 'John %' GROUP BY name ORDER BY 2 DESC
SELECT name, COUNT(movieid) FROM casting JOIN actor WHERE name LIKE 'John %' GROUP BY name ORDER BY COUNT(movieid) DESC

4. Select the result that would be obtained from the following code: SELECT title FROM movie, casting, actor WHERE name='Paul Hogan' AND movieid=movie.id AND actorid=actor.id AND ord = 1

Table-A
Table-B
Table-C
Table-D
Table-E

5. Select the statement that lists all the actors that starred in movies directed by Ridley Scott

SELECT name FROM movie JOIN casting AND actor ON movie.id = movieid AND actor.id = actorid WHERE ord = NULL AND director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')
SELECT name FROM movie JOIN casting JOIN actor ON movie.id = movieid OR actor.id = actorid WHERE ord = 1 AND director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')
SELECT name FROM movie JOIN casting ON movie.id = movieid JOIN actor ON actor.id = actorid WHERE ord = 1 AND actorid = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')
SELECT name FROM movie JOIN casting ON movie.id = movieid JOIN actor ON actor.id = actorid WHERE ord = 1 AND director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')
SELECT name FROM movie JOIN casting ON movie.id = actorid JOIN actor ON actor.id = movieid WHERE director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')

6. Select the statement showing all movies with budget bigger than ALL movie with Harrison Ford is incorrect

SELECT title FROM movie WHERE budget > ALL (SELECT budget FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid WHERE name = 'Harrison Ford')
SELECT title FROM movie WHERE budget > ALL (SELECT budget FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid OR name = 'Harrison Ford')
SELECT title FROM movie WHERE budget > (SELECT MAX(budget) FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid WHERE name = 'Harrison Ford')
SELECT title FROM movie WHERE budget > ALL (SELECT budget FROM movie JOIN casting ON movie.id = movieid JOIN actor ON actor.id = actorid WHERE name = 'Harrison Ford')
SELECT title FROM movie WHERE budget > (SELECT MAX(budget) FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid AND name = 'Harrison Ford')

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