Difference between revisions of "JOIN Quiz 2"

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JOIN Quiz - part 2
 
JOIN Quiz - part 2
 
<div class='db_ref' style='background:none'>
 
<table class="zoo">
 
  <caption>movie</caption>
 
    <tr>
 
      <th>Field name</th>
 
      <th>Type</th>
 
      <th>Notes</th>
 
    </tr>
 
 
    <tr>
 
      <td notranslate="1">id</td>
 
      <td notranslate="1">INTEGER</td>
 
      <td>An arbitrary unique identifier</td>
 
    </tr>
 
 
    <tr>
 
      <td notranslate="1">title</td>
 
      <td notranslate="1">CHAR(70)</td>
 
      <td>The name of the film - usually in the language of the
 
      first release.</td>
 
    </tr>
 
 
    <tr>
 
      <td notranslate="1">yr</td>
 
      <td notranslate="1">DECIMAL(4)</td>
 
      <td>Year of first release.</td>
 
    </tr>
 
 
    <tr>
 
      <td notranslate="1">director</td>
 
      <td notranslate="1">INT</td>
 
      <td>A reference to the actor table.</td>
 
    </tr>
 
 
    <tr>
 
      <td notranslate="1">budget</td>
 
      <td notranslate="1">INTEGER</td>
 
      <td>How much the movie cost to make (in a variety of currencies unfortunately).</td>
 
    </tr>
 
    <tr>
 
      <td notranslate="1">gross</td>
 
      <td notranslate="1">INTEGER</td>
 
      <td>How much the movie made at the box office.</td>
 
    </tr>
 
</table>
 
 
<table class="zoo">
 
  <caption>actor</caption>
 
    <tr>
 
      <th>Field name</th>
 
 
      <th>Type</th>
 
 
      <th>Notes</th>
 
    </tr>
 
 
    <tr>
 
      <td notranslate="1">id</td>
 
 
      <td notranslate="1">INTEGER</td>
 
 
      <td>An arbitrary unique identifier</td>
 
    </tr>
 
 
    <tr>
 
      <td notranslate="1">name</td>
 
 
      <td notranslate="1">CHAR(36)</td>
 
 
      <td>The name of the actor (the term actor is used to refer to
 
      both male and female thesps.)</td>
 
    </tr>
 
</table>
 
 
<table class="zoo">
 
  <caption>casting</caption>
 
    <tr>
 
      <th>Field name</th>
 
 
      <th>Type</th>
 
 
      <th>Notes</th>
 
    </tr>
 
 
    <tr>
 
      <td notranslate="1">movieid</td>
 
 
      <td notranslate="1">INTEGER</td>
 
 
      <td>A reference to the movie table.</td>
 
    </tr>
 
 
    <tr>
 
      <td notranslate="1">actorid</td>
 
 
      <td notranslate="1">INTEGER</td>
 
 
      <td>A reference to the actor table.</td>
 
    </tr>
 
 
    <tr>
 
      <td notranslate="1">ord</td>
 
 
      <td notranslate="1">INTEGER</td>
 
 
<td>The ordinal position of the actor in the cast list. The
 
star of the movie will have ord value 1 the co-star will have
 
value 2, ...</td>
 
</tr>
 
</table>
 
</div>
 
  
 
<quiz shuffle=none display=simple>
 
<quiz shuffle=none display=simple>
{Which of the following statements lists the unfortunate directors of the movies which have caused financial loses? (gross <  budget)
+
{Select the statement which lists the unfortunate directors of the movies which have caused financial loses (gross <  budget)
 
|type="()"}
 
|type="()"}
 
- SELECT JOIN(name FROM actor, movie ON actor.id:director WHERE gross < budget) GROUP BY name  
 
- SELECT JOIN(name FROM actor, movie ON actor.id:director WHERE gross < budget) GROUP BY name  
Line 129: Line 17:
 
- SELECT * FROM actor JOIN casting ON actor.id = actorid AND movie ON movie.id = movieid
 
- SELECT * FROM actor JOIN casting ON actor.id = actorid AND movie ON movie.id = movieid
 
+ SELECT * FROM actor JOIN casting ON actor.id = actorid JOIN movie ON movie.id = movieid
 
+ SELECT * FROM actor JOIN casting ON actor.id = actorid JOIN movie ON movie.id = movieid
 +
 +
{Select the statement that shows the list of actors called 'John' by order of number of movies in which they acted
 +
|type="()"}
 +
- SELECT name, COUNT(movieid) FROM actor JOIN casting ON actorid=actor.id WHERE name IN 'John %' GROUP BY name ORDER BY 2
 +
- SELECT name, COUNT(movieid) FROM actor JOIN casting ON actorid=actor.id WHERE name LIKE 'J%' GROUP BY name ORDER BY 2 DESC
 +
+ SELECT name, COUNT(movieid) FROM casting JOIN actor ON actorid=actor.id WHERE name LIKE 'John %' GROUP BY name ORDER BY 2 DESC
 +
- SELECT name, COUNT(movieid) FROM casting JOIN actor WHERE (actorid ON actor.id) AND name LIKE 'John %' GROUP BY name ORDER BY 2 DESC
 +
- SELECT name, COUNT(movieid) FROM casting JOIN actor WHERE name LIKE 'John %' GROUP BY name ORDER BY COUNT(movieid) DESC
 +
 +
{Select the result that would be obtained from the following code: SELECT title FROM movie, casting, actor WHERE name='Paul Hogan' AND movieid=movie.id AND actorid=actor.id AND ord = 1
 +
<table style='float:left'><caption>Table-A</caption><tr><td>"Crocodile" Dundee</td><td>1</td></tr><tr><td>Crocodile Dundee in Los Angeles</td><td>1</td></tr><tr><td>Flipper</td><td>1</td></tr><tr><td>Lightning Jack</td><td>1</td></tr></table>
 +
<table style='float:left'><caption>Table-B</caption><tr><td>"Crocodile" Dundee</td></tr><tr><td>Crocodile Dundee in Los Angeles</td></tr><tr><td>Flipper</td></tr><tr><td>Lightning Jack</td></tr></table>
 +
<table style='float:left'><caption>Table-C</caption><tr><td>"Crocodile" Dundee</td></tr><tr><td>Paul Hogan</td></tr><tr><td>1</td></tr></table>
 +
<table style='float:left'><caption>Table-D</caption><tr><td>"Crocodile" Dundee</td><td>Paul Hogan</td><td>1</td></tr><tr><td>Crocodile Dundee in Los Angeles</td><td>Paul Hogan</td><td>1</td></tr><tr><td>Flipper</td><td>Paul Hogan</td><td>1</td></tr><tr><td>Lightning Jack</td><td>Paul Hogan</td><td>1</td></tr></table>
 +
<table style='float:left'><caption>Table-E</caption><tr><td>"Crocodile" Dundee</td><td>Paul Hogan</td></tr><tr><td>Crocodile Dundee in Los Angeles</td><td>Paul Hogan</td></tr><tr><td>Flipper</td><td>Paul Hogan</td></tr><tr><td>Lightning Jack</td><td>Paul Hogan</td></tr></table>
 +
|type="()"}
 +
- Table-A
 +
+ Table-B
 +
- Table-C
 +
- Table-D
 +
- Table-E
 +
 +
{Select the statement that lists all the actors that starred in movies directed by Ridley Scott
 +
|type="()"}
 +
- SELECT name FROM movie JOIN casting AND actor ON movie.id = movieid AND actor.id = actorid WHERE ord = NULL AND director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')
 +
- SELECT name FROM movie JOIN casting JOIN actor ON movie.id = movieid OR actor.id = actorid WHERE ord = 1 AND director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')
 +
- SELECT name FROM movie JOIN casting ON movie.id = movieid JOIN actor ON actor.id = actorid WHERE ord = 1 AND actorid = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')
 +
+ SELECT name FROM movie JOIN casting ON movie.id = movieid JOIN actor ON actor.id = actorid WHERE ord = 1 AND director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')
 +
- SELECT name FROM movie JOIN casting ON movie.id = actorid JOIN actor ON actor.id = movieid WHERE director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')
 +
 +
{Select the statement showing all movies with budget bigger than ALL movie with Harrison Ford is '''incorrect'''
 +
|type="()"}
 +
- SELECT title FROM movie WHERE budget > ALL (SELECT budget FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid WHERE name = 'Harrison Ford')
 +
+ SELECT title FROM movie WHERE budget > ALL (SELECT budget FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid OR name = 'Harrison Ford')
 +
- SELECT title FROM movie WHERE budget > (SELECT MAX(budget) FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid WHERE name = 'Harrison Ford')
 +
- SELECT title FROM movie WHERE budget > ALL (SELECT budget FROM movie JOIN casting ON movie.id = movieid JOIN actor ON actor.id = actorid WHERE name = 'Harrison Ford')
 +
- SELECT title FROM movie WHERE budget > (SELECT MAX(budget) FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid AND name = 'Harrison Ford')
 +
 +
{Select the result that would be obtained from the following code: SELECT title, yr FROM movie, casting, actor WHERE name='Robert De Niro' AND movieid=movie.id AND actorid=actor.id AND ord = 3
 +
<table style='float:left'><caption>Table-A</caption><tr><td>A Bronx Tale</td><td>1993</td><td>3</td></tr><tr><td>Bang the Drum Slowly</td><td>1973</td><td>3</td></tr><tr><td>Limitless</td><td>2011</td><td>3</td></tr></table>
 +
<table style='float:left'><caption>Table-B</caption><tr><td>A Bronx Tale</td><td>1993</td></tr><tr><td>Bang the Drum Slowly</td><td>1973</td></tr><tr><td>Limitless</td><td>2011</td></tr></table>
 +
<table style='float:left'><caption>Table-C</caption><tr><td>A Bronx Tale</td><td>3</td></tr><tr><td>Bang the Drum Slowly</td><td>3</td></tr><tr><td>Limitless</td><td>3</td></tr></table>
 +
<table style='float:left'><caption>Table-D</caption><tr><td>A Bronx Tale</td></tr><tr><td>Bang the Drum Slowly</td></tr><tr><td>Limitless</td></tr></table>
 +
<table style='float:left'><caption>Table-E</caption><tr><td>A Bronx Tale</td><td>Robert De Niro</td><td>1993</td></tr><tr><td>Bang the Drum Slowly</td><td>Robert De Niro</td><td>1973</td></tr><tr><td>Limitless</td><td>Robert De Niro</td><td>2011</td></tr></table>
 +
|type="()"}
 +
- Table-A
 +
+ Table-B
 +
- Table-C
 +
- Table-D
 +
- Table-E
  
 
</quiz>
 
</quiz>
  
 
[[Category:Quizzes]]
 
[[Category:Quizzes]]

Revision as of 19:59, 7 September 2012

JOIN Quiz - part 2

<quiz shuffle=none display=simple> {Select the statement which lists the unfortunate directors of the movies which have caused financial loses (gross < budget) |type="()"} - SELECT JOIN(name FROM actor, movie ON actor.id:director WHERE gross < budget) GROUP BY name - SELECT name FROM actor INNER JOIN movie BY actor.id = director HAVING gross < budget + SELECT name FROM actor INNER JOIN movie ON actor.id = director WHERE gross < budget - SELECT name FROM actor INNER JOIN movie ON actor.id:director WHERE gross < budget - SELECT name FROM director INNER JOIN movie ON movie.id = director.id WHERE gross < budget

{Select the correct example of JOINing three tables |type="()"} - SELECT * FROM actor JOIN casting BY actor.id = actorid JOIN movie BY movie.id = movieid - SELECT * FROM actor JOIN casting ON actor.id = actorid AND JOIN movie ON movie.id = movieid - SELECT * FROM actor JOIN casting JOIN movie ON actor.id = actorid AND movie.id = movieid - SELECT * FROM actor JOIN casting ON actor.id = actorid AND movie ON movie.id = movieid + SELECT * FROM actor JOIN casting ON actor.id = actorid JOIN movie ON movie.id = movieid

{Select the statement that shows the list of actors called 'John' by order of number of movies in which they acted |type="()"} - SELECT name, COUNT(movieid) FROM actor JOIN casting ON actorid=actor.id WHERE name IN 'John %' GROUP BY name ORDER BY 2 - SELECT name, COUNT(movieid) FROM actor JOIN casting ON actorid=actor.id WHERE name LIKE 'J%' GROUP BY name ORDER BY 2 DESC + SELECT name, COUNT(movieid) FROM casting JOIN actor ON actorid=actor.id WHERE name LIKE 'John %' GROUP BY name ORDER BY 2 DESC - SELECT name, COUNT(movieid) FROM casting JOIN actor WHERE (actorid ON actor.id) AND name LIKE 'John %' GROUP BY name ORDER BY 2 DESC - SELECT name, COUNT(movieid) FROM casting JOIN actor WHERE name LIKE 'John %' GROUP BY name ORDER BY COUNT(movieid) DESC

{Select the result that would be obtained from the following code: SELECT title FROM movie, casting, actor WHERE name='Paul Hogan' AND movieid=movie.id AND actorid=actor.id AND ord = 1

Table-A
"Crocodile" Dundee1
Crocodile Dundee in Los Angeles1
Flipper1
Lightning Jack1
Table-B
"Crocodile" Dundee
Crocodile Dundee in Los Angeles
Flipper
Lightning Jack
Table-C
"Crocodile" Dundee
Paul Hogan
1
Table-D
"Crocodile" DundeePaul Hogan1
Crocodile Dundee in Los AngelesPaul Hogan1
FlipperPaul Hogan1
Lightning JackPaul Hogan1
Table-E
"Crocodile" DundeePaul Hogan
Crocodile Dundee in Los AngelesPaul Hogan
FlipperPaul Hogan
Lightning JackPaul Hogan

|type="()"} - Table-A + Table-B - Table-C - Table-D - Table-E

{Select the statement that lists all the actors that starred in movies directed by Ridley Scott |type="()"} - SELECT name FROM movie JOIN casting AND actor ON movie.id = movieid AND actor.id = actorid WHERE ord = NULL AND director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott') - SELECT name FROM movie JOIN casting JOIN actor ON movie.id = movieid OR actor.id = actorid WHERE ord = 1 AND director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott') - SELECT name FROM movie JOIN casting ON movie.id = movieid JOIN actor ON actor.id = actorid WHERE ord = 1 AND actorid = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott') + SELECT name FROM movie JOIN casting ON movie.id = movieid JOIN actor ON actor.id = actorid WHERE ord = 1 AND director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott') - SELECT name FROM movie JOIN casting ON movie.id = actorid JOIN actor ON actor.id = movieid WHERE director = (SELECT id FROM actor WHERE name LIKE 'Ridley Scott')

{Select the statement showing all movies with budget bigger than ALL movie with Harrison Ford is incorrect |type="()"} - SELECT title FROM movie WHERE budget > ALL (SELECT budget FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid WHERE name = 'Harrison Ford') + SELECT title FROM movie WHERE budget > ALL (SELECT budget FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid OR name = 'Harrison Ford') - SELECT title FROM movie WHERE budget > (SELECT MAX(budget) FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid WHERE name = 'Harrison Ford') - SELECT title FROM movie WHERE budget > ALL (SELECT budget FROM movie JOIN casting ON movie.id = movieid JOIN actor ON actor.id = actorid WHERE name = 'Harrison Ford') - SELECT title FROM movie WHERE budget > (SELECT MAX(budget) FROM movie JOIN casting JOIN actor ON movie.id = movieid AND actor.id = actorid AND name = 'Harrison Ford')

{Select the result that would be obtained from the following code: SELECT title, yr FROM movie, casting, actor WHERE name='Robert De Niro' AND movieid=movie.id AND actorid=actor.id AND ord = 3

Table-A
A Bronx Tale19933
Bang the Drum Slowly19733
Limitless20113
Table-B
A Bronx Tale1993
Bang the Drum Slowly1973
Limitless2011
Table-C
A Bronx Tale3
Bang the Drum Slowly3
Limitless3
Table-D
A Bronx Tale
Bang the Drum Slowly
Limitless
Table-E
A Bronx TaleRobert De Niro1993
Bang the Drum SlowlyRobert De Niro1973
LimitlessRobert De Niro2011

|type="()"} - Table-A + Table-B - Table-C - Table-D - Table-E

</quiz>