# Using Null Quiz

Using Null Quiz

teacher
id dept name phone mobile
101 1 Shrivell 2753 07986 555 1234
102 1 Throd 2754 07122 555 1920
103 1 Splint 2293
104 Spiregrain 3287
105 2 Cutflower 3212 07996 555 6574
dept
id name
1 Computing
2 Design
3 Engineering

1. Which of the following uses of JOIN is correct?

 SELECT teacher.name, dept.name FROM teacher JOIN dept ON (dept = id) SELECT teacher.name, dept.name FROM teacher, dept INNER JOIN ON (teacher.dept = dept.id) SELECT teacher.name, dept.name FROM teacher, dept JOIN WHERE(teacher.dept = dept.id) SELECT teacher.name, dept.name FROM teacher OUTER JOIN dept ON dept.id SELECT teacher.name, dept.name FROM teacher LEFT OUTER JOIN dept ON (teacher.dept > dept.id)

2. Select the correct statement that shows the name of department which employs Cutflower

 SELECT dept.name FROM teacher JOIN dept ON (dept.id = (SELECT dept FROM teacher WHERE name = 'Cutflower')) SELECT dept.name FROM teacher JOIN dept ON (dept.id = teacher.dept) WHERE dept.id = (SELECT dept FROM teacher HAVING name = 'Cutflower') SELECT dept.name FROM teacher JOIN dept ON (dept.id = teacher.dept) WHERE teacher.name = 'Cutflower' SELECT dept.name FROM teacher JOIN dept WHERE dept.id = (SELECT dept FROM teacher WHERE name = 'Cutflower') SELECT name FROM teacher JOIN dept ON (id = dept) WHERE id = (SELECT dept FROM teacher WHERE name = 'Cutflower')

3. Which of following uses of JOIN shows list of all the departments and number of employed teachers?

 SELECT dept.name, COUNT(*) FROM teacher LEFT JOIN dept ON dept.id = teacher.dept SELECT dept.name, COUNT(teacher.name) FROM teacher, dept JOIN ON dept.id = teacher.dept GROUP BY dept.name SELECT dept.name, COUNT(teacher.name) FROM teacher JOIN dept ON dept.id = teacher.dept GROUP BY dept.name SELECT dept.name, COUNT(teacher.name) FROM teacher LEFT OUTER JOIN dept ON dept.id = teacher.dept GROUP BY dept.name SELECT dept.name, COUNT(teacher.name) FROM teacher RIGHT JOIN dept ON dept.id = teacher.dept GROUP BY dept.name

4. Using `SELECT name, dept, COALESCE(dept, 0) AS result FROM teacher` on `teacher` table will:

 display 0 in result column for all teachers display 0 in result column for all teachers without department do nothing - the statement is incorrect set dept value of all teachers to 0 set dept value of all teachers without department to 0

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